2. Find the total flux ΦE passing through the sides of a cube 1.00 m on a side if a point charge of 5.00 × 10−6 C is located at its center.
by Gauss's law:
ΦE=qin/ε0\Phi_E=q_{in}/\varepsilon_0ΦE=qin/ε0
where qin is charge enclosed by the surface
so,
ΦE=5⋅10−6/8.85⋅10−12=5.65⋅105\Phi_E=5\cdot10^{-6}/8.85\cdot10^{-12}=5.65\cdot10^5ΦE=5⋅10−6/8.85⋅10−12=5.65⋅105 N⋅\cdot⋅m2/C
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments