Question

2. Find the total flux ΦE passing through the sides of a cube 1.00 m on a side if a point charge of 5.00 × 10−6 C is located at its center.

Answer 1

Using Gauss's law $\phi=\frac{Q}{\Epsilon}$

$\phi_T=\frac{5×10^{-6}}{8.854×10^{-12}}$

$=5.647×10^5Nm^2/C$

For one side $\phi=\frac{1}{6}×5.647×10^5$

$=9.412×10^4Nm^2/C$

For all sides $=6\phi$

$=5.647×10^5Nm^2/C$