Question #276421

A cylindrical rubber insulated cable has a diameter of 0.18 inch and an insulation thickness of 0.25 inch. If the specific resistance 0f rubber is 1014 ohm-cm, determine the insulation resistance per 1000 ft length of the cable.

1
Expert's answer
2021-12-09T09:23:00-0500

Solution;

Given;

d=0.18in

r=0.09inr=0.09in

t=0.25int=0.25in

The outer radius is;

R=0.09+0.25=0.34inR=0.09+0.25=0.34in

Specific resistance of rubber;

δ=1014Ωcm=1012Ωm\delta=10^{14}\Omega-cm=10^{12}\Omega-m

Length L=1000ft=305mL=1000ft=305m

Insulation resistance;

Rin=δ2πLln(Rr)R_{in}=\frac{\delta}{2πL} ln(\frac Rr)

Rin=10122×π×305ln(0.340.09)=693.569MΩR_{in}=\frac{10^{12}}{2×π×305}ln(\frac {0.34}{0.09})=693.569M\Omega


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