Question #276020

Flashlight batteries is having electro-motive force of 1.5 v and internal resistance of one owns are connected to a resistor

of 5 ohms calculate the current in this resistor if the cell are connected to series or parallel


Expert's answer

The current:


I=VR+r=1.51+5=0.25 A.I=\frac V{R+r}=\frac{1.5}{1+5}=0.25\text{ A}.


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