Answer to Question #275048 in Electric Circuits for kate

Question

You move a charge q from r_i = 9.1 m to r_f = 4.6 m from a fixed charge Q = 10.7 nC. What is the difference in potential for these two positions?

Answer 1

given properties:

$r_1=9.1m$

$r_2=4.6m$

$q=10.7nC = 10.7·10^{-9}C$

$k = 9·10^9\frac{N·m^2}{C^2}$

$\Delta\varphi - ?$

difference in potential for these two positions is $\Delta\varphi=k·\large\frac{q}{r_1-r_2}$ $= \large\frac{9·10^9·10.7·10^{-9}}{4.5}$ $=21.4V$