What is the temperature change when 69, point, 0, k, J,
69.0kJ is transferred to a 1, point, 20, k, g,
1.20kg object with a specific heat capacity of 250, J, slash, left bracket, k, g, degrees, C, right bracket,
250J/(kg∘
C)?
Explanations & Calculations
\qquad\qquad \begin{aligned} \small \Delta \theta&=\small \frac{Q}{mc}\\ &=\small \frac{ 69.0\,kJ}{1.20\,kg\times250\,Jkg^{-1}\, {^0} C^{-1}}\\ &=\small0.23\,^0C \end{aligned}
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