Answer to Question #274897 in Electric Circuits for zaynna

Question #274897


What is the temperature change when 69, point, 0, k, J,


69.0kJ is transferred to a 1, point, 20, k, g,


1.20kg object with a specific heat capacity of 250, J, slash, left bracket, k, g, degrees, C, right bracket,


250J/(kg∘

C)?



1
Expert's answer
2021-12-03T12:45:03-0500

Explanations & Calculations


  • Use the equation Q=mcΔθ\small Q = mc\Delta \theta for this.

\qquad\qquad \begin{aligned} \small \Delta \theta&=\small \frac{Q}{mc}\\ &=\small \frac{ 69.0\,kJ}{1.20\,kg\times250\,Jkg^{-1}\, {^0} C^{-1}}\\ &=\small0.23\,^0C \end{aligned}


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