Answer to Question #274897 in Electric Circuits for zaynna

Question

What is the temperature change when 69, point, 0, k, J,

69.0kJ is transferred to a 1, point, 20, k, g,

1.20kg object with a specific heat capacity of 250, J, slash, left bracket, k, g, degrees, C, right bracket,

250J/(kg∘

C)?

Answer 1

Explanations & Calculations

• Use the equation $\small Q = mc\Delta \theta$ for this.

$\qquad\qquad \begin{aligned} \small \Delta \theta&=\small \frac{Q}{mc}\\ &=\small \frac{ 69.0\,kJ}{1.20\,kg\times250\,Jkg^{-1}\, {^0} C^{-1}}\\ &=\small0.23\,^0C \end{aligned}$