You are filling a cylindrical drum (D = 22.5 in., H = 33.5 in.) with water flowing from a garden faucet at a rate of 10 GPM. How long will you have to wait to fill the drum? Express you answer in minutes.
Explanations & Calculations
V=πD24H=π(22.5 in)24(33.5 in)=13319.9 in3=13319.9 (0.0254 m)3=0.218 m3=0.218 l=0.218×0.264 gallons=0.058 gallons\qquad\qquad \begin{aligned} \small V&=\small \pi\frac{D^2}{4}H\\ &=\small \pi\frac{(22.5\,in)^2}{4}(33.5\,in)\\ &=\small 13319.9\,in^3\\ &=\small 13319.9\,(0.0254\,m)^3\\ &=\small 0.218\,m^3=0.218\,l\\ &=\small 0.218\times0.264\,gallons\\ &=\small 0.058\,gallons \end{aligned}V=π4D2H=π4(22.5in)2(33.5in)=13319.9in3=13319.9(0.0254m)3=0.218m3=0.218l=0.218×0.264gallons=0.058gallons
t=0.058 G10 Gpm=0.0058 min=0.0058×60 s=3.5 s\qquad\qquad \begin{aligned} \small t&=\small \frac{0.058\,G}{10\,Gpm}\\ &=\small 0.0058\,min\\ &=\small 0.0058\times60\,s\\ &=\small 3.5\,s \end{aligned}t=10Gpm0.058G=0.0058min=0.0058×60s=3.5s
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