Answer to Question #270942 in Electric Circuits for pet

Question

-6e-3tcos(15t)nc

Answer 1

if charge:

$q(t)=-6e^{-3t}cos(15t)$ nC

then current:

$I(t)=dq/dt=18e^{-3t}cos(15t)+90e^{-3t}sin(15t)$ nA