Answer the Following Problem
Direction: Find all the currents and voltages across each resistor and cell in the following circuits;
1.
2.
3.
4.
5.
6.
for left loop:
4I3+3I4=124I_3+3I_4=124I3+3I4=12
for right loop:
2I2−4I3=−52I_2-4I_3=-52I2−4I3=−5
I1=I2+I3I_1=I_2+I_3I1=I2+I3
I4=I2+I3I_4=I_2+I_3I4=I2+I3
then:
4I3+3(I2+I3)=124I_3+3(I_2+I_3)=124I3+3(I2+I3)=12
I2=4−7I3/3I_2=4-7I_3/3I2=4−7I3/3
2(4−7I3/3)−4I3=−52(4-7I_3/3)-4I_3=-52(4−7I3/3)−4I3=−5
I3=13⋅3/26=39/26=1.5I_3=13\cdot3/26=39/26=1.5I3=13⋅3/26=39/26=1.5 A
I2=4−7⋅1.5/3=0.5I_2=4-7\cdot 1.5/3=0.5I2=4−7⋅1.5/3=0.5 A
I1=I4=0.5+1.5=2I_1=I_4=0.5+1.5=2I1=I4=0.5+1.5=2 A
U2=2⋅0.5=1U_2=2\cdot0.5=1U2=2⋅0.5=1 V
U3=4⋅1.5=6U_3=4\cdot1.5=6U3=4⋅1.5=6 V
U4=3⋅2=6U_4=3\cdot2=6U4=3⋅2=6 V
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