THE SUBSTATION BUSBAR IS MADE UP OF 2 INCHES ROUND COPPER BARS 240in LONG.
WHAT IS THE RESISTANCE OF EACH BAR IF RESISTIVITY IS 1.724 x 10-6 OHM-CM?
R=2in=0.0254×2=0.0508m0.0254\times2=0.0508m0.0254×2=0.0508m
L=240 in =240×0.0254=6.096m=240\times0.0254=6.096m=240×0.0254=6.096m
ρ=1.724×10−8Ωm\rho=1.724\times10^{-8}\Omega mρ=1.724×10−8Ωm
We know that
R=ρLAR=\frac{\rho L}{A}R=AρL
Put value
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