Question #266229

For a series LRC circuit, if L=30H, R= 0.05 ohms and C= 5.8F, what is the time required for the amplitude of the charge stored by the capacitor to be halved?


1
Expert's answer
2021-11-15T17:51:09-0500

We know that

Charge

q=q0(1etRC)q=q_0(1-e^{\frac{-t}{RC}})

q=q0(1et0.05×5.8)q=q_0(1-e^{\frac{-t}{0.05\times5.8}})

q02=q0(1et0.05×5.8)\frac{q_0}{2}=q_0(1-e^{\frac{-t}{0.05\times5.8}})

12=et0.05×5.8\frac{1}{2}=e^{-\frac{t}{0.05\times5.8}}

ln2=t0.05×5.8ln2=\frac{t}{0.05\times5.8}

t=0.29×ln2=0.202sect=0.29\times ln2=0.202sec


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