Question

a) Two resistors R1 = 3Ω and R2 = 8Ω are connected in parallel with a battery of 12V. Calculate the voltage that flows through each resistor. 

Answer 1

Solution;

Since the resistors are connected is parallel;

$V=V_1=V_2=12V$

The current flowing through each resistor is;

$I_1=\frac VR=\frac{12}{3}=4A$

$I_2=\frac VR=\frac{12}{8}=1.5A$