a) Two resistors R1 = 3Ω and R2 = 8Ω are connected in parallel with a battery of 12V. Calculate the voltage that flows through each resistor.
Solution;
Since the resistors are connected is parallel;
"V=V_1=V_2=12V"
The current flowing through each resistor is;
"I_1=\\frac VR=\\frac{12}{3}=4A"
"I_2=\\frac VR=\\frac{12}{8}=1.5A"
Comments
Leave a comment