Answer to Question #261503 in Electric Circuits for eissa

Question #261503

Suppose many capacitors, each with 𝐢 =90.0 μ𝐹, are connected in parallel across a battery

with a potential difference of βˆ†π‘‰ =160.0 𝑉. How many capacitors are needed to store 95.6 J

of energy?


1
Expert's answer
2021-11-08T17:12:26-0500

C=90ΞΌFβˆ†V=160voltU=95.6JC=90\mu F\\βˆ†V=160volt\\U=95.6J

U=12Cβ€²βˆ†V2U=\frac{1}{2}C'βˆ†V^2

Assume n capacitor connected in parallel combination

C'=nC

U=12nCβˆ†V2U=\frac{1}{2}nCβˆ†V^2


n=2UCβˆ†V2=2Γ—95.6Γ—90Γ—10βˆ’6Γ—160Γ—160=82n=\frac{2U}{Cβˆ†V^2}=\frac{2\times95.6\times}{90\times10^{-6}\times160\times160}=82

n=82


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