Answer to Question #261487 in Electric Circuits for eissa

Electric Circuits

Question #261487

How much energy is stored in the 180 μ𝐹 capacitor of a camera flash unit charged to

300.0 𝑉?

Expert's answer

"Enery, E=\\frac{1}{2}CV^2=\\frac{1}{2}\\times 180 \\times 10^{-6} \\times 300^2=8.1J"

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