Answer to Question #261487 in Electric Circuits for eissa

Question

How much energy is stored in the 180 μ𝐹 capacitor of a camera flash unit charged to

300.0 𝑉?

Answer 1

$Enery, E=\frac{1}{2}CV^2=\frac{1}{2}\times 180 \times 10^{-6} \times 300^2=8.1J$