Answer to Question #261029 in Electric Circuits for Williams

Question

A battery of e.m.f E and negligible internal resistance R1 and R2 connected in parallel. Calculate the current through R2 in terms of R1

Answer 1

$R_1,R_2$ Connected parallel combination

$R_{eq}=\frac{{R_1}{R_2}}{R_1+R_2}$

Current flow $R_1$ Resistance

$I_1=\frac{E}{R_1}$

Current flow in$R_2$ Resistance

$I_2=\frac{E}{R_2}$