Question #260916

A current of 3 A flows through a resistor for 6 minutes. Determine the power dissipated in the resistor if 3V existed across the resistor.

1
Expert's answer
2021-11-04T18:04:12-0400

Power

P=i2RP=i^2R

R=VI=33=1AR=\frac{V}{I}=\frac{3}{3}=1A

P=32×1=9WP=3^2\times1=9W

Work(W)=Pt=9×360=3240JPt=9\times 360=3240J


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