a) A wire of a certain length (a=0.0065/°C) has a resistance of 4Ω (at 20°C). Find its resistance at 80°C.
"R=R_0(1+a\u0394T) \\\\\nR = 4(1 + 0.0065 \\times (80-20)) \\\\\nR = 4 \\times 1.39 = 5.56 \\; \\Omega"
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