Question #259303

In a series connection solve for the total capacitance.


C1 = 3.5 x 10^-12 F

C2 = 2.41 x 10^-12 F

C3 = 1.13 x 10^-12 F

V = 1700 V


1
Expert's answer
2021-11-01T12:54:29-0400

Solution;

Capacitance in series is given as;

1CT=1C1+1C2+1C3+....\frac{1}{C_T}=\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}+....

By substitution;

1CT=13.5×1012+12.41×1012+11.13×1012\frac{1}{C_T}=\frac{1}{3.5×10^{-12}}+\frac{1}{2.41×10^{-12}}+\frac{1}{1.13×10^{-12}}

1CT=1.5856×1012\frac{1}{C_T}=1.5856×10^{12}

CT=11.5856×1012C_T=\frac{1}{1.5856×10^{-12}}

CT=6.307×1013C_T=6.307×10^{-13} F




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