Answer to Question #259303 in Electric Circuits for Howard

Question

In a series connection solve for the total capacitance.

C1 = 3.5 x 10^-12 F

C2 = 2.41 x 10^-12 F

C3 = 1.13 x 10^-12 F

V = 1700 V

Answer 1

Solution;

Capacitance in series is given as;

$\frac{1}{C_T}=\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}+....$

By substitution;

$\frac{1}{C_T}=\frac{1}{3.5×10^{-12}}+\frac{1}{2.41×10^{-12}}+\frac{1}{1.13×10^{-12}}$

$\frac{1}{C_T}=1.5856×10^{12}$

$C_T=\frac{1}{1.5856×10^{-12}}$

$C_T=6.307×10^{-13}$ F