Feq=−800+120−720=−321 NMA=1200×450−720×700−800×200=−12400 N⋅mmF_{eq} = -800+120-720 = -321 \;N \\ M_A = 1200 \times 450 -720 \times 700 -800 \times 200 = -12400 \;N \cdot mmFeq=−800+120−720=−321NMA=1200×450−720×700−800×200=−12400N⋅mm
Using Varignon’s theorem
Feq×x=MAx=124000320=387.5 mmF_{eq} \times x = M_A \\ x = \frac{124000}{320} = 387.5 \;mmFeq×x=MAx=320124000=387.5mm
Answer: 387.5 mm
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