Question #248183
  1. Given a dc bias of 0.5mA and a bandwidth of 10 kHz, calculate for the noise current.
1
Expert's answer
2021-10-08T11:47:41-0400

Root mean square value of the shot noise current in is given by the Schotty formula:


In=2IqΔB\sqrt{2\Iota{q}\Delta\Beta}



Where:

I\Iota =Dc current in Amperes

q= charge of an electron in Coulombs

Δ\DeltaB\Beta = the bandwidth in Hertz



Substituting


In= 2×0.5×103×1.602×1019×10×103\sqrt{2×0.5×10^{-3}×1.602×10^{-19}×10×10^3}

2×0.5×103×1.602×1019×10×103\sqrt{2×0.5×10^{-3}×1.602×10^{-19}×10×10^3}



In =1.266×109A×10^{-9}A

=1.266nA




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