Question

there are 3 resistors in parallel with resistances of 3Ω,4Ω and 11Ω. What is the total resistance of the parallel combination?

Answer 1

$\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}$

$\frac{1}{R}=\frac{1}{3}+\frac{1}{4}+\frac{1}{11}$

$R=\frac{44+33+12}{12\times11}=\frac{89}{132}=0.6742\Omega$