Question #246074

If q1=-8.2C and q2=4.9C, what is the electric potential difference Va-Vb (in gigavolts GV)?


Expert's answer

Let distances:

d1=1d_1=1 m, d2=0.5d_2=0.5 m

Then:

VaVb=k(q1/d1q2/d2)=9109(8.2+9.8)=14.4V_a-V_b=k(q_1/d_1-q_2/d_2)=9\cdot10^9(-8.2+9.8)=14.4 GV


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