Question #238810
A 700 W lamp was connected to a supply that a 5A current was flowing through the lamp. What is that resistance of the lamp
1
Expert's answer
2021-09-21T11:05:07-0400

power, P=I2RP=I^2R

R=PI2=70052=R=\frac{P}{I^2}=\frac{700}{5^2}= 28Ω28\Omega


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