Gives
l=120m
R=16 ohm
We know that
ρ=RAlσ=lRA\rho=\frac{RA}{l}\\\sigma=\frac{l}{RA}ρ=lRAσ=RAl
Put value
σ=12016×A=7.5Amho/m\sigma=\frac{120}{16\times A}=\frac{7.5}{A} mho/mσ=16×A120=A7.5mho/m
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