Question

A heating instrument has 12 resistors and
they are placed vertically and have a uniform
reducing power. The powers of the first,
second, third and fourth resistors are 3000,
2600, 2200, and 1800 respectively. Find the
power of the resistor

Answer 1

Since we have a series arrangement for these four resistors, we proceed to find the total power as

$P_T=P_1+P_2+{P_3}+{P_4}$

We substitute to find P_T:

$P_T= \Big( {3000\,W}+{2600\,W}+{2200\,W}+{1800\,W} \Big) \\ \implies P_T= 9600\, W$

In conclusion, the power of the resistor is about 9600 W.

Reference:

• Sears, F. W., & Zemansky, M. W. (1973). University physics.