Answer to Question #237889 in Electric Circuits for Neilmar

Question

A coil has 100 turns. A current of 10A is passed through the coil. The coil develops

Answer 1

Explanations & Calculations

• Depending on the given data, the question can be thought to asking for the magnetic field produced by it.
• The magnetic field within the coil (good only for the field inside of it) is given by

$\qquad\qquad \begin{aligned} \small \vec{B}&=\small \mu.n.i=\mu.\Big(\frac{N}{L}\Big).i\\ &=\small 4\pi 10^{-7}Hm^{-1}\times100\,turns\,m^{-1}\times10A\\ &=\small \bold{1.26\times10^{-3}T} \end{aligned}$

• Note that the n in the equation is the turns per unit length of the coil & the "100 turns" provided in the question was assumed to be n to get the answer as the question itself lacks some information.