Given that VS = 3V, VBE = 0.3V, IC = 9mA, and R1 = 1kΩ, calculate the base current of the transistor Q1 using KVL. Also find the current gain ( ) of the transistor Q1
Using KVL
3=0.3+1000IE2.7=1000IEIE=2.7mAIE=IC+IBIB=IE−IC=2.7−9=−6.3mA3=0.3+1000I_E\\ 2.7=1000I_E\\ I_E=2.7mA\\ I_E=I_C+I_B\\ I_B=I_E-I_C=2.7-9=-6.3mA\\3=0.3+1000IE2.7=1000IEIE=2.7mAIE=IC+IBIB=IE−IC=2.7−9=−6.3mA
Base current is 6.3mA
Current gain beta β\betaβ is given by
β=ICIB=96.3=1.4\beta=\dfrac{I_C}{I_B}=\dfrac{9}{6.3}=1.4β=IBIC=6.39=1.4
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