Answer to Question #223397 in Electric Circuits for Jiska

Question

A charge ‘Q’ is placed at the center of a cube of side l , what is the electric flux passing through two opposite faces of the cube is

Answer 1

We know that

Gauss law of electric flux

$\phi=\frac{Q}{\epsilon_0}\rightarrow(1)$

Where Q=charge

equation (1) represent electric flux due to six face of cube

electric flux due to each face of cube

$\phi'=\frac{\phi}{6}\rightarrow(2)$

equation (1) and eqution (2) we can written as

$\phi'=\frac{Q}{6\epsilon}$

the electric flux passing through two opposite faces of the cube

$\phi'=2\times\frac{Q}{6\epsilon_0}=\frac{Q}{3\epsilon_0}$