Answer to Question #221627 in Electric Circuits for Sahaj

Question

Two capacitors of capacitances 1μF and 0.01μF are charged to the same potential,

which will give more intense electric shock if touched? Explain.

Answer 1

Gives

$C_1=1\mu F,C_2=0.1\mu F,$

Both charged same potential mean connected is parallel combination

Potential =V

Charge

$$Q_1=C_1V=1\times10^{-6}\times V=10^{-6} V C$$

$$Q_2=0.01\times10^{-6}\times V =10^{-8}V C$$

$Q_1>Q_2$

Q_1. more intense electric shock if touched Because $Q_1$ Is high camparision $Q_2$