A valtage of 200v is connected across a capacitor of a capacitance of 2.5uF. calculate the charge deposited on each plate
Energy stored in 2.5 μf2.5\ \mu f2.5 μf capacitor ;
U2.5=0.5×C×V2U2.5=0.5×2.5×10−6×2002U_{2.5}=0.5\times C\times V^2\\U_{2. 5}=0.5×2.5×10 ^{-6}×200^2U2.5=0.5×C×V2U2.5=0.5×2.5×10−6×2002
U2.5=0.05JU_{2.5}=0.05JU2.5=0.05J
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