Electric field
E=kqr2λ=qlq=λlE=kλlr2E=\frac{kq}{r^2}\\\lambda=\frac{q}{l}\\q=\lambda l\\E=\frac{k\lambda l}{r^2}E=r2kqλ=lqq=λlE=r2kλl
Put value
E=9×109×2×l22E=\frac{9\times10^9\times2\times l}{2^2}E=229×109×2×l
E=4.5×109×lE=4.5\times10^9\times lE=4.5×109×l N/c
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments