Question #218533
The electric potential at the surface of a charged sphere is 10 V at its surface. Find the value of potential and electric field at its centre
1
Expert's answer
2021-07-19T15:28:34-0400

Gives

Vs=kQrV_s=\frac{kQ}{r}

Q charge distributed by surface

Vs=10VV_s=10V

Centr potential

Vc=kQrV_c=\frac{kQ}{r} Where r<R


Then Vc=10VV_c=10V

Electric field

Es=KqR2E_s=\frac{Kq}{R^2} Where R=r

Ein=kQrR3E_{in}=\frac{kQr}{R^3}

Centre electric field

Put value

r=0

Ec=0E_c=0



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