Answer to Question #218533 in Electric Circuits for Somyajit biswal

Question

The electric potential at the surface of a charged sphere is 10 V at its surface. Find the value of potential and electric field at its centre

Answer 1

Gives

$V_s=\frac{kQ}{r}$

Q charge distributed by surface

$V_s=10V$

Centr potential

$V_c=\frac{kQ}{r}$ Where r<R

Then $V_c=10V$

Electric field

$E_s=\frac{Kq}{R^2}$ Where R=r

$E_{in}=\frac{kQr}{R^3}$

Centre electric field

Put value

r=0

$E_c=0$