Question #218062

A copper cable is 1.2km long and has a cross-sectional Area of 5mm².Find it's resistance at 80°C if at 20°C the resistivity of copper is 0.02×10^-6 ohm m and it's temperature coefficient of resistance is 0.004/°C.


1
Expert's answer
2021-07-21T09:52:12-0400

Resistance at 20°C R20=ρla=0.02×106×1.2×103M5×106=4.8ohmsR_{20}=\frac{\rho{l}}{a} = \frac{0.02×10^{-6}×1.2×10^3M}{5×10{^-6}}=4.8ohms

Resistance at 80°C R80=R20[1+α20(8060)]=4.8[1+0.004(60)]=5.95ΩR_{80}=R_{20}[1+\alpha_{20}(80-60)] = 4.8[1+0.004(60)]= 5.95Ω

R80=5.95ΩR_{80}= 5.95Ω

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