Gives
Gauss law
∇.E=−ρϵ0\nabla.E=-\frac{\rho}{\epsilon_0}∇.E=−ϵ0ρ
ρ=0\rho=0ρ=0
∇.E=0\nabla.E=0∇.E=0
Volume charge density zero then
Divergence of electric field is zero
We know that continuity equation.
∇.J=−dρdt\nabla.J=-\frac{d\rho}{dt}∇.J=−dtdρ
∇.J=0\nabla.J=0∇.J=0
Divergence of current density is zero
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