Answer to Question #215144 in Electric Circuits for Anusha

Question

two metallic charge spheres wbhose radii are 20cm and 10cm respectively, have each 150mC charge. the common potential after they are connected by a conducting wire is

Answer 1

Given quantities:

$R_1 = 20cm = 0.2m$

$R_2 = 10cm = 0.1m$

$q_1=q_2=150mC=15*10^{-2}C$

$Common\space potential = \large\frac{Total \space Charge}{Total\space capacitance}=\large\frac{q_1+q_2}{C_1+C_2}=\frac{q_1+q_2}{4\pi e_o(R_1+R_2)} = \frac{150*10^{-6}*2}{4*3.14*8.85*10^{-12}*0.3}$ = $9*10^6V$