Calculate electric field at a distance of 40 cm from the centre of sphere of radius 15 cm
carries a charge of 1.6 µc
Gives
r=40cm
Q=1.6μc\mu cμc
R=15cm
E=kQr2E=\frac{kQ}{r^2}E=r2kQ
E=9×109×1.6×10−60.42E=\frac{9\times10^{9}\times1.6\times10^{-6}}{0.4^2}E=0.429×109×1.6×10−6
E=9×104N/cE=9\times10^4N/cE=9×104N/c
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