Answer to Question #211308 in Electric Circuits for anuj

Electric Circuits

Question #211308

An inductor of 250 mH has a reactance of 1450 Ω. What is the frequency of the current in the inductor?

Expert's answer

$X_L=2\pi f L$

$1450=2\pi \times f\times 250/1000=$ $2\pi \times f\times 0.25$

$f=\frac{1450}{2\pi \times 0.25}= 923.0987 Hz$

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