Answer to Question #210064 in Electric Circuits for Jay

Question

A circuit has a current of 1340 mA and a voltage of 11 V. What is the power of 

the circuit? What is the resistance of the circuit?

Answer 1

Gives

Current (I)=1340mA

Voltage=11V

Power=$IV$

$$P=1340\times10^{-3}\times11=14.74watt$$

Resistance

$$R=\frac{P}{I^2}=\frac{14.74}{(1340\times10^{-3})^2}=8 .20\Omega$$