Question #209263

An electic circuit consists of the following components:

-resistor R1 and R2 connected in series, and

-resistor R3 connected in parallel with R2.

If R1 =R3kohms, R2=3.5komhs,and R3=9kohms.

1.draw the circuit diagram.

2.calculate the voltage across R3 if the applied voltage is 12V.

3.calculate the current passing R1 and R3.


1
Expert's answer
2021-06-21T16:29:48-0400


Gives

R1=3KΩR_1=3K\Omega

R2=3.5KΩR_2=3.5K\Omega

R3=3.5KΩR_3=3.5K\Omega

V=12V

Part(a)



Parralled combination voltage drop same

R=R2R3R'=R_2||R_3

R=2.52ΩR'=2.52\Omega

I=2.6AI=2.6A

Potential R3R_3

V=IR=2.5×2.6V=6.55VV=IR'=2.5\times2.6V=6.55V

Voltage across R3R_3


Rnet=R2R3+R1R_{net}=R_2||R_3+R_1

Rnet=6013ΩR_{net}=\frac{60}{13}\Omega


I1=126013A=135A=2.6AI_1=\frac{\frac{12}{60}}{13}A=\frac{13}{5}A=2.6A

Current R3R_3 Resistance

I3I2=R2R3=3.59=718\frac{I_3}{I_2}=\frac{R_2}{R_3}=\frac{3.5}{9}=\frac{7}{18}


I3=725×2.6I_3=\frac{7}{25}\times2.6 =0.728A












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