Answer to Question #208765 in Electric Circuits for Nusaiba

Question

Three identical bulbs are connected to a cell in series. Which bulb has the largest current through it?

Answer 1

Gives

Three bulb are series combination

Cell voltage =V

Current=$I$

Three resistance

$R_1=R$

$R_2=R$

$P_1=I^2R$

$R_3=R$

$P_2=I^2R$

$P_3=I^2R$

All three resistance are equal and current flow same in series combination then Power

P_net=P₁+P₂+P₃

$P_{net}=3P$

$P=\frac{P_{net}}{3}$

$P_1=P_2=P_3=P=I^2R$

All three resistance are same current flow

And all three resistance are same power