Question

 a circuit consisting of 9 volt battery and two 4ohm resistors connected in series. How many Coulomb flows through each resistor in a second?

Answer 1

Gives

Battery (V)=9V

$R_1=R_2=4\Omega$

Both are series combination

$R_{eq}=R_1+R_2=4+4=8\Omega$

$V=IR$

$I=\frac{V}{R}=\frac{9}{8}=1.125A$

Each resistance flow charg(coulamb )

$Q=It=1\times1.125=1.125C$