If m=5 kg and M=8 kg, find the acceleration of the masses and the tension of the rope
8g−T=8aT−g=5a8g-T=8a\\ T-g=5a8g−T=8aT−g=5a
Adding the two equations gives
3g=13aa=3g13g=9.8m/s2a=3×9.813a=2.26m/s23g=13a\\ a=\frac{3g}{13}\\ g=9.8m/s^2\\ a=\frac{3\times 9.8}{13}\\ a=2.26m/s^2\\3g=13aa=133gg=9.8m/s2a=133×9.8a=2.26m/s2
To get the Tension T
T=5(g+a)T=5(9.8+2.26)T=60.3NT=5(g+a)\\ T=5(9.8+2.26)\\ T=60.3NT=5(g+a)T=5(9.8+2.26)T=60.3N
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