Answer to Question #208090 in Electric Circuits for Charlton

Question

a capacitance of 20uf and a resistance of 10052 are connected in series across a 120v, 60Hz, if the capacitive reactance is 13352. find the impedance of the circuit. b). what is the magnitude of the circuit current? c). calculate the potential difference across the capacitor.

Answer 1

Gives

C=20$\mu F$

R=10055 ohm

n=60Hz

V=120V

$X_c=13352\Omega$

Impedance of circuit

$$Z=\sqrt{R^2+X^2_c}=\sqrt{10055^2+13352^2}=16714.63\Omega$$

Current

$$I=\frac{V}{Z}=\frac{120}{16714.63}=7.17\times10^{-3}A=7.17mA$$

Potential difference across the capacitor

$V=I\times X_C$

$$V_c=7.17\times10^{-3}\times13352 V=95.73\Omega$$