Question

Calculate the instantaneous power of an ac circuit that has a maximum voltage of 240v and a maximum current of 0.24A with a phase angle of 30 degrees.

Answer 1

Gives

$I_m=0.24A$

$V_m=240V$

$V_{RMS}=\frac{V_m}{\sqrt2}$

$I_{RMS}=\frac{I_{m}}{\sqrt2}$

$P_{ac}=I_{RMS}V_{RMS}cos\phi$

$P_{ac}=\frac{I_m V_m}{2}cos\phi$

$P_{ac}=\frac{0.24\times240}{2}cos30°$

$P_{ac}=24.94W$