Answer to Question #208071 in Electric Circuits for Charlton

Question

a pair of adjacent coils has a mutual inductance of 1.06h. determine the average emf induced in the secondary circuit when the current in the primary circuit changes to 9.5A in 0.0336s

Answer 1

We know that

emf = -M*dl/dt

M = -1.06H

dl = 9.5A

dt = 0.0336s

Thus

emf = -1.06 * 9.5/0.0336s

= -299.70

= - 300 Volts