A coaxial cable consists of a solid inner conductor of radius a =0.2 m carrying total current of 5A, surrounded by a concentric cylindrical tube of inner radius b=0.4 m and outer radius c=0.6m carrying current of 5A. The conductors carry equal and opposite currents I distributed uniformly across their cross-sections. Determine the magnetic field at a distance r=0.5m from the axis.
Gives
a=0.2m
Current (I)=5A
b=0.4m
c=0.6m
r=0.5m
We know that
Ampear law in closed loop
Put value
Area Flow current =
Area Flow current=
Area Flow current =
Put value
Comments
Leave a comment