Answer to Question #204594 in Electric Circuits for pumpkin

Question

A 32−Ω resistor and a 20−Ω resistor are connected in parallel, and the combination is connected across a 240-V dc line. (a) What is the resistance of the parallel combination? (b) What is the total current through the parallel combination? (c) What is the current through each resistor?

Answer 1

$R_1=32\Omega$

$R_2=20\Omega$

V=240V

R_eq=$\frac{R_1\times R_2}{R_1+R_2}$

$R_{eq}=\frac{32\times20}{32+20}$

$R_{eq}=12.30\Omega$

Current

$I=\frac{V}{R_{net}}=\frac{240}{12.39}$

$I=19.51Amp$

$R_1$ Flow current

$I_1=\frac{R_2}{R_1+R_2}\times I$

$I_1=\frac {20}{52}\times19.51$ =7.50A

$I_2=\frac{R_1}{R_1+R_2}\times I$

$I_2=\frac {32}{52}\times19.51$ =12.00A