Question

Evaluate the circuit shown at the right. What is the charge of capacitor C3? 20V C1=6 C2=6 C4= 2 C6=1

Answer 1

$C_{12} = C_1 + C_2 = 12µF$

$C_{eq} =[ \frac{1}{C_{12}} + \frac{1}{C_{13}}]^{−1} = 1.5µF.$

$Q_2 = V_2C_2 = 8µC$