Evaluate the circuit shown at the right. What is the charge of capacitor C3? 20V C1=6 C2=6 C4= 2 C6=1
"C_{12} = C_1 + C_2 = 12\u00b5F"
"C_{eq} =[ \\frac{1}{C_{12}} + \\frac{1}{C_{13}}]^{\u22121} = 1.5\u00b5F."
"Q_2 = V_2C_2 = 8\u00b5C"
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