The voltage applied to a circuit is v=100 sin(wt+30 º) and current flowing in the circuit is i= 15 sin(wt+60 º). induced emf. Determine: 1. Impedance 2.Phase angle between voltage and current 3.Active Power 4.Power Factor.
Gives
V=100sin(wt+30°)V=100sin(wt+30°)V=100sin(wt+30°)
I=15sin(wt+60°)I=15sin(wt+60°)I=15sin(wt+60°)
Impedance (Z)
ZR2+(XL−Xc)2Z\sqrt{R^2+{(X_L-X_c})^2}ZR2+(XL−Xc)2
XL=Xc=0X_L=X_c=0XL=Xc=0
Then
Z=R=10015=6.66Ω\frac{100}{15}=6.66\Omega15100=6.66Ω
Phase difference
Active power
P=IV2cosϕP=\frac{IV}{2}cos\phiP=2IVcosϕ
Put value
P=100×152cos30°P=\frac{100\times15}{2}cos30°P=2100×15cos30°
P=650 W
Power factor
Cosϕ=RZCos\phi =\frac{R}{Z}Cosϕ=ZR
R=VIR=\frac{V}{I}R=IV
R=10015R=\frac{100}{15}R=15100
Cosϕ=6.666.66=1Cos\phi=\frac{6.66}{6.66}=1Cosϕ=6.666.66=1
ϕ=cos−11=0°\phi=cos^{-1}1=0°ϕ=cos−11=0°
Power factorϕ=0°\phi=0°ϕ=0°
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