A capacitor is a square with an angle a = 3cm with a distance between the ammeters e = 2mm. Calculate the capacitance of the capacitor if the electric field is air.
Gives
Square side (a)=3cm
Distance between palate (d)=2mm
Area(A)=(3×10−2)2=9×10−4m2(3\times10^{-2})^2=9\times10^{-4}m^2(3×10−2)2=9×10−4m2
C=Aϵ0dC=\frac{A\epsilon_0}{d}C=dAϵ0
C=9×10−4×8.85×10−122×10−3C=\frac{9\times10^{-4}\times8.85\times10^{-12}}{2\times10^{-3}}C=2×10−39×10−4×8.85×10−12
C=3.98×10−12FC=3.98\times10^{-12}FC=3.98×10−12F
Electric field
E=QAϵ0E=\frac{Q}{A\epsilon_0}E=Aϵ0Q
E=Q9×10−4×8.85×10−12E=\frac{Q}{9\times10^{-4}\times8.85\times10^{-12}}E=9×10−4×8.85×10−12Q
E=Q7.97×10−15E=\frac{Q}{7.97\times10^{-15}}E=7.97×10−15Q V/m
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